x(x+19)+k^2(1-x)+2k(x-3)-7=0

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Solution for x(x+19)+k^2(1-x)+2k(x-3)-7=0 equation: 


Simplifying
x(x + 19) + k2(1 + -1x) + 2k(x + -3) + -7 = 0

Reorder the terms:
x(19 + x) + k2(1 + -1x) + 2k(x + -3) + -7 = 0
(19 * x + x * x) + k2(1 + -1x) + 2k(x + -3) + -7 = 0
(19x + x2) + k2(1 + -1x) + 2k(x + -3) + -7 = 0
19x + x2 + (1 * k2 + -1x * k2) + 2k(x + -3) + -7 = 0
19x + x2 + (1k2 + -1k2x) + 2k(x + -3) + -7 = 0

Reorder the terms:
19x + x2 + 1k2 + -1k2x + 2k(-3 + x) + -7 = 0
19x + x2 + 1k2 + -1k2x + (-3 * 2k + x * 2k) + -7 = 0
19x + x2 + 1k2 + -1k2x + (-6k + 2kx) + -7 = 0

Reorder the terms:
-7 + -6k + 2kx + 1k2 + -1k2x + 19x + x2 = 0

Solving
-7 + -6k + 2kx + 1k2 + -1k2x + 19x + x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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